. In the figure, AB = 20 m, BC = 21 m, AD = 10 m and
DE = 10.5 m. Find the area of the shaded region.
C
21 m
D
10 m
10.5 m
A
B
E
+ 20 m
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11
Answer:
Area Of Triangle Abc = 1/2 (AB)(BC) = 1/2 × 20 × 21
= 21×10 = 210m²
area of triangle ade = 1/2 (AD)(DE) =1/2 × 10 × 10.5 = 5×10.5 = 52.5m²
=> area of shaded part
= area of triangle ABC - area of triangle ADE
= 210 - 52.5 = 157.5m²
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Answer:
Are u from any branch of APSACS?
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