Question

In the figure AB = 6 centimetres , AC = 5 centimetres , BAC = 90 0. CD is parallel to AB . Find the area of triangle BAC ..​

Answer 1

Answer:

Area of ΔBAC = 15 $cm^{2}$

Step-by-step explanation:

∵ ΔBAC is right angled triangle

∴ Ar(ΔBAC) = $\frac{1}{2}lb$

                    $=\frac{1}{2}(5)(6)\\ =(5)(3)\\=15 cm^{2}$

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Answer 2

Answer:

Hey!! Ur answer:

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