Question

In the figure AB = 6 centimetres , AC = 5 centimetres ,< BAC = 90° .CD is parallel to AB .a) Find the area of triangle BAC .

Answer 1

Solution :-

given that, in ∆CAB,

→ AB = 5 cm

→ AC = 6 cm

→ ∠CAB = 90°

so,

→ Area of right angled ∆CAB = (1/2) * Base * Perpendicular height .

then, taking AC as perpendicular height and AB as base we get,

→ Area of ∆BAC = (1/2) * 5 * 6 = 15 cm² (Ans.)

Hence, area of ∆BAC is equal to 15 cm² .

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