Question

In the Figure AB =6cm, angle AOB =60, Find angle OAB​

Answer 1

Answer:

Given: In the Figure, it is given that AB =6cm, angle AOB =60

To find: Angle OAB

Step-by-step explanation:

Concept: Two angles connecting the equal lines to the third side of an isosceles triangle are equal.

Assume AOB is a triangle in a circle, with O being a circle and A and B being points on the circumference.

Since AO and OB are radii of the circle ∴ ΔAOB is a isosceles triangle

∠A =∠B

A+B+C=180°

2A = 180°- 60°

A= 60°

In other way method:

OA = OB ( Radius of of the circle ) --------- ( 1 )

therefore, here, < OAB = < OBA

[ Angles opposite to equal sides of a ∆ are equal ]

< AOB + < OAB + OBA = 180°

< AOB = 60° [Given in the question]

60° + < OAB + < OAB = 180°

[ < OAB = < OBA ]

2< OAB = 180 - 60

< OAB = 120/ 2

< OAB = 60°

Follow the following method to find angle in a triangle:

• Subtract the two given angles from 180° :
• Put the two angles of a triangle into the formula and use this method: a + b + c = 180°

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