in the figure AB= AC and AD is the perpendicular drawn from A to BC Prove that triangle ADB is congruent to triangle ADC
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⇒ In △ABC,AB=AC and AD is perpendicular bisector of BC. The property by which△ADB is not congruent to △ADC is AAAproperty
⇒ It is given that AB and AC are equal so one side should be in congruent property.
⇒ So, AAA property does not contain any side.
∴ Correct answer is option D.
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Answer:
Step-by-step explanation:
In △ADB and △ADC
AB=AC (given)
AD=AD (common side)
∠ADB=∠ADC=90° (As AD⊥BC)
△ADB≅△ADC by RHS property
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