Question

In the figure AB=AC and angle ABC=50°and AM is perpendicular to BC then angle MAB=?

Answer 1

∠MAB = 40°

Step-by-step explanation:

In a ΔABC,

Given,

AB = AC,

∠ABC = 50°

Construction:

Construct AM perpendicular to BC.

⇒∠AMB = 90°

In ΔABC,

Since AB = AC

        ∠ABC = ∠ACB (Angle opposite to equal sides are always equal)

       ∠ABC = ∠ACB = 50°

In ΔABM,

∠ABM + ∠BAM + ∠AMB = 180° (Angle sum property of a triangle)

50° + ∠BAM + 90° = 180°

140° + ∠BAM = 180°

∠BAM = 40°

or ∠MAB = 40°