in the figure AB=AC and CF are respectively
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PLEASE TELL WHERE IS THE PICTURE .
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draw the diagram
AB=AC given
<ECB=<FBC base angles are equal in an isosceles triangle
CF bisects <ACB given
EB bisects <ABC given
<FCB<EBC if 2 equal angles are bisected then each half of one angle equals each half of the other angle
CB=CB identity
therefore triangle ECB is congruent to triangle FCB by ASA
FC=EB corresponding parts of congruent triangles are congruent
therefore triangle ECB is congruent to triangle FCB by SAS also
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