Question

In the figure ab and ac are the two tangents drawn from the poin a to the circle with centre 0.if

Answer 1

Answer:

140Degrees

Step-by-step explanation:

Tangent is perpendicular to radius at point of contact.

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘In a quadrilateral, the sum of the angles is 360∘. 

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘In a quadrilateral, the sum of the angles is 360∘. ∠BAC+∠BOC+∠ABO+∠ACO=360∘

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘In a quadrilateral, the sum of the angles is 360∘. ∠BAC+∠BOC+∠ABO+∠ACO=360∘∴∠BAC+∠BOC=180∘

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘In a quadrilateral, the sum of the angles is 360∘. ∠BAC+∠BOC+∠ABO+∠ACO=360∘∴∠BAC+∠BOC=180∘                      ∠BOC=180∘−40∘

Tangent is perpendicular to radius at point of contact.So, ∠ABO=∠ACO=90∘In a quadrilateral, the sum of the angles is 360∘. ∠BAC+∠BOC+∠ABO+∠ACO=360∘∴∠BAC+∠BOC=180∘                      ∠BOC=180∘−40∘                      ∠BOC=140∘

Hope This will Help You

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