Question

In the figure AB and AC are the two tangents drawn from the point A to the
circle with centre O. If | BOC = 130° then find
BAC.
B
00130°
​

Answer 1

Answer:

Tangent is perpendicular to radius at point of contact.

So, ∠ABO=∠ACO=90∘

In a quadrilateral, the sum of the angles is 360∘. 

∠BAC+∠BOC+∠ABO+∠ACO=360∘

∴∠BAC+∠BOC=180∘

                      ∠BOC=180∘−40∘

                      ∠BOC=140∘

So, option C is the answer

Step-by-step explanation:

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