Question

in the figure AB and AC are the two tangents drawn from the point A to the circle with centre O. if angle BOC = 130 °. then find angle BAC
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Answer 1

Answer:

180-130=50....hope helps u

Step-by-step explanation:

Answer 2

Step-by-step explanation:

We know that the tangent is always perpendicular to the radius.

Therefore, we can say that the quadrilateral formed with ABOC is always equal to 360

.

and given BOC=130

and we also know the angles between radius and tangent equal to 90

o

By calculating, we get:

360^o=90^o+130^o+90^0+BAC

BAC=360 −90 −90 −130

BAC=50

.