In the figure AB and AC are the two tangentS drwn from the point A to the circle with centre O if BOC = 130 find the BAC
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Step-by-step explanation:
Given: | BOC = 130 To bind = IBAL=2
In quadrilateral OBCA BOC + OBA + | BAC + ACQ = 360° 130+ 90° +1BAS + 90° = 360°
| BAC = 360 -310 1BAC = 50 degrees
(OBLAB, DCIAC)
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