Question

in the figure ab and ac are two tangents drawn from a to the centre of circle of if boc =l30°find bac ​

Answer 1

Answer:

Step-by-step explanation:

Tangent is perpendicular to radius at point of contact.

So, ∠ABO=∠ACO=90∘

In a quadrilateral, the sum of the angles is 360∘.  

∠BAC+∠BOC+∠ABO+∠ACO=360∘

∴∠BAC+∠BOC=180∘

                     ∠BOC=180∘−40∘

                     ∠BOC=140∘

Hope this will helps You

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Answer 2

Answer:

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