In the figure, AB and CD diameter O is
the centre, B = 40°, then the angle
subtended by BD at O is
(A) 100°
(B) 80°
(C) 20°
(D) 90°
Answers
Step-by-step explanation:
Answer:
Let us assume that 1000 g of goods cost Rs. 100.
Since he makes a Profit of 20%, the Selling Price would be:
\begin{gathered}\implies Profit\: \% = \dfrac{(SP - CP)}{CP } \times 100\\\\\\\implies 20 = \dfrac{ SP - 100}{ 100} \times 100\\\\\\\implies 20 = SP - 100\\\\\\\implies SP = 100 + 20 = \boxed{ \bf{ Rs. 120}}\end{gathered}
⟹Profit%=
CP
(SP−CP)
×100
⟹20=
100
SP−100
×100
⟹20=SP−100
⟹SP=100+20=
Rs.120
Hence for 1000 grams of goods, he sells them for Rs. 120 by which he earns a profit of 20%.
Now, it is given that, he also uses a weighing machine which weighs the goods 20% less than the original weight.
Hence 1000 g of goods in his weighing machine would weigh:
\begin{gathered}\implies \text{Actual weight} = 1000 - \dfrac{20}{100} \times 1000\\\\\\\implies \text{Actual Weight} = 1000 - 200 = \boxed{ \bf{800 g}}\end{gathered}
⟹Actual weight=1000−
100
20
×1000
⟹Actual Weight=1000−200=
800g
Hence his machine would show the weight of 800 g to be equal to 1000 g.
Therefore, for 1000 g = Rs. 120, then for 800 g the actual selling price would be:
\begin{gathered}\implies \text{SP for 800 g } = \dfrac{800 \times 120}{1000}\\\\\\\implies \text{ SP for 800 g} = \boxed{ \bf{Rs.\:\:96}}\end{gathered}
⟹SP for 800 g =
1000
800×120
⟹ SP for 800 g=
Rs.96
But, the shopkeeper is selling it for Rs. 120. Hence profit made here is:
\begin{gathered}\implies Profit\: \% = \dfrac{120 - 96}{96} \times 100\\\\\\\implies Profit\: \% = \dfrac{24}{96} \times 100\\\\\\\implies Profit\: \% = \dfrac{100}{4} \\\\\\\implies Profit\: \% = \boxed{ \bf{ 25\:\%}}\end{gathered}
⟹Profit%=
96
120−96
×100
⟹Profit%=
96
24
×100
⟹Profit%=
4
100
⟹Profit%=
25%
Therefore the net profit gained by the dishonest shopkeeper is 25%.
Answer:
20°
Step-by-step explanation:
In attachment
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