Question

In the figure, AB = BC and O is the center of the circle Prove that Bo bisects ABC​

Answer 1

Answer:

Given: In the figure, AB = CB and O is the centre of the circle. To Prove: BO bisects ∠ABC. Construction: Join OA and OC. Proof : In ∆OAB and ∆OCB, OA = OC [Radii of the same circle] AB = CB [Given] OB = OB [Common] ∴ ∆OAB ≅ ∆OCB [By SSS] ∴ ∠ABO = ∠CBO [By cpctc] ⇒ BO bisects ∠ABC. Read more on Sarthaks.com - https://www.sarthaks.com/75542/in-figure-ab-cb-and-o-is-the-centre-of-the-circle-prove-that-bo-bisects-abc?show=75545#a75545

Step-by-step explanation:

hope it's helpful