In the figure, AB ||CD and CD ||EF. Also, EA ⊥ AB if angle BEF = 55°, F ind the values of x, y and z.
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Solution:
angle z = 90 - 55 = 35 degree.
angle x = 180 - (90+35) = 55 degree.
180-55 = 125 degree.
angle y = angle x = 125 degree
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- AB || CD and CD || EF and BE is a transversal
- EA ⊥ AB and ∠BEF = 55°
To find :-
- The value of x,y and z
Solution :-
we know that, interior angle on the same side of the transversal are 180°
y + 55° = 180°
y = 180°- 55°
y = 125°
y = x
AB || CD , corresponding angle
so,
x = 125°
Now,
∠ EAB + ∠ FEA = 180°
90° + (z + 55) = 180°
145° + z = 180°
z = 180° - 145°
z = 35°
Hence,the value of x ,y and z will be 125° , 125° and 35°.
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