Question

In the figure, AB || CD and FP bisects EFB. If
ZCGH = 150°, find the value of EFP.​

Answer 1

angle FGD=150(opposite angles)

angle EFB=Angle FGD=150

SINCE FP BISECTS ANGLE EFB

IT WILL BE 150/2(bisector divides equally)

Therefore angle EPF=150/2=75 degrees

75 is the answer

Answer 2

In the figure, AB || CD and FP bisects EFB. If

ZCGH = 150°, find the value of EFP.

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