In the figure AB=CD and 'O' is the midpoint of AC
and BD. Show that traingle AOB is congruent to COD
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In triangles AOC and BOD, we have
AO = BO (O, the midpoint of AB);
∠AOC=∠BOD, (vertically opposite angles);
CO=OD, (O, the midpoint of CD)
So by SAS postulate we have
△AOC≅△BOD.
Hence, AC = BD, as they are corresponding parts of congruent triangles.
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it is congruent by sss
Step-by-step explanation:
AB=CD (GIVEN)
ao=oc (since it is mid point of ac and ao and oc are the two parts formed by mid poit o )
bo=do (same reason as above)
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aob=cod
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