in the figure AB||CD and PQ||RS, find angle 1,2,3,4,5,6and7
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BLQ=3=32. (Vertically opposite angle)
LMS=MLP=90. (Alternate interior angle)
3+2=90
32+2=90
2=90-32=58
2+1+QLB=180
58+1+32=180
1=180-90=90
2=LMD=58
LMD+6=90
58+6=90
6=90-58
6=32
6+5=180
32+5=180
5=180-32
5=148
4=6. (Alternate interior angle)
4+7+LMD=180
32+7+58=180
7=180-90
7=90
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