Question

In the figure, AB||CD||EF,GL is a straight line and GJ is a transversal.Find the value of angle JGL, angle KLF and angle HJL​

Answer 1

Answer:

JGL=52

KLF=142

HJL=90

hope it helps

Answer 2

Step-by-step explanation:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\AB \parallel BC \parallel EF \\ GJ \: is \: straight \: line \: \\ GL \: is \: transversal \: line \\ \angle MJE = 90 \degree \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ \angle JGL, \angle KLF, \: and \: \angle \: HJL \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ \red{ \underline{vertically \: opposite \: angle}}\\ \angle \: HJL = \angle MJE = 90 \degree \\ \boxed{\angle \: HJL = 90 \degree} \\ \angle \: JGL+ \angle \: BGL= \angle \: JGB \\ \angle \: JGL + 38 \degree = 90 \degree \\ \boxed{ \angle \: JGL =52 \degree} \\ \blue{ \underline{\large{AB \parallel BC}}} \\ \blue{\mathfrak{ \underline{\large{corresponding \: angle}}}} \\ \angle DKL = \angle \: BGL = 38 \degree \\ \blue{ \underline{\large{BC \parallel EF}}}\\ \blue{\mathfrak{ \underline{\large{co - interior \: angle}}}}\\ \angle DKL + \angle KLF = 180 \degree \\ 38 \degree + \angle KLF = 180 \degree \\ \boxed{\angle KLF = 142 \degree} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$