Question

In the figure, AB || CD. find the value of x .

Please Help.
​

Answer 1

$\huge{\fcolorbox{cyan}{black}{\red{ANSWER:-}}}$

• From E, draw EF || AB || CD. EF || CD and CE is the transversal.
• ∴∠DCE+∠CEF=180o        [∵ Co-interior angles]
• ⇒xo+∠CEF=180o⇒∠CEF=(180−xo)
• Again, EF || AB and AE is the transversal.
• ∠BAE+∠AEF=180o      [∵ Co-interior angles]
• ⇒105o+∠AEC+∠CEF=180o
• ⇒105o+25o+(180o−xo)=180o
• ⇒310−xo=180o
• Hence, x=130o

Hope it helps..!

Answer 2

Answer:

please mark as brainlist answer and thanked also