Question

in the figure AB//CD, find the value of
x. y, and z
​

Answer 1

Answer:

50 + 60 + y = 180

y = 70

now, 25 + x = 50 ( corresponding angles)

x = 25

now, in triangle PQR

x + y + z = 180

70 + 25 + z = 180

105 + z = 180

z = 75

Answer 2

Answer:

x=25°,y=70° and z=85°

Step-by-step explanation:

angle EPD + angle DPR + angle QPR = 180°

50°+60°+y=180°

y=180°-60°-50°

y=70°

angle CPQ + angle QPR + angle DPR =180°

angle CPQ=180°-70°-60°

angle CPQ = 50°

angle CPQ=angle PQB

50°=x+25°

x=25°

In ∆ PQR, by angle sum property,

x+y+z=180°

25°+70°+z=180°

z=180°-95°

z=85°

Here is your answer, hope it helps you....