Question

In the figure AB||CD, If x=4/3y and y=3/8z find angle BCD, angle ABC and angle BAD​

Answer 1

∠BCD = 96°  , ∠ABC = 84°  , ∠BAD  = 60°

Step-by-step explanation:

AB||CD

=> x + y + z = 180

=> 4y/3 + y + 8y/3 = 180

=> 4y + 3y + 8y = 540

=> 15y = 540

=> y = 36

x = 4y/3 = 4 * 36/3 = 48

x = 48

z = 8y/3 = 8 * 36/3 = 96

z = 96

∠BCD = z = 96°

∠ABC = x + y = 48 + 36 = 84°

∠BAD  = 180 - x - 72

= 180  - 48 - 72

= 60°

Learn more:

2. In Fig. 3.29. if AB || CD. CD || EF and y:z=3:7,find x. - Brainly.in

https://brainly.in/question/11444712

4. In the figure, angle PQR = 122°, angle QRS = x andangle RST = y ...

https://brainly.in/question/12846836

Answer 2

Step-by-step explanation:

if x=4y/3

if y=3z/8

y/3/8= z

8y/3 = z

now,

since, AB||CD

x + y+ z + = 180 [Consecutive Interior Angle]

4y/3 + y + 8y/3 = 180

12y +3 y = 180 × 3

15y = 540

y = 540/15

y = 36

Finally,

x = 4y/3

x = 4×36/3

x= 48

y = 36

z = 8y/3

z = 8 × 36/3

z = 96

Therefore,

angle BCD = z = 96

angle ABC = x + y = 84

angle BAD = 180 - x - 72

BAD = 180 - 48 - 72

BAD = 60

HOPE YOU LIKE IT . IF IT WAS HELPFUL PLEASE LIKE SHARE AND COMMENT