Question

In the figure AB||CD if x=4y/3 and y=3z/8 .Find angle BCD,angleABC,angleBAD 11 question ?? How to solve

Answer I will mark the first one as BRAINLIEST

Answer 1

Solution :-

ABIICD

• x+y+z = 180

4y/3+y+8y/3 = 180

4y+3y+8y = 540

15y = 540

y = 36

• x = 4y/3 = 4* 36/3 = 48
• x = 48

• z = 8y/3 = 8* 36/3 = 96
• z = 96

Angle BCD = z = 96 degree

Angle ABC = x+y = 48+36 = 84

Angle BAD = 180-x - 72

= 180-48-72 = 60 degree

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