In the figure, AB || CD, t is their transversal. if m∠FGD = 5x and m∠EFB = 120 - x, find m∠EFB and m∠FGD.
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angle EFB = angle FGD. (AB parallel to CD)
120-x = 5x
120= 5x+x
120= 6x
120÷6=x
x=20.
Now , angle EFB = angle FGD= 5x = 5 × 20
= 100
Therefore,
angle EFB = angle FGD = 100°
120-x = 5x
120= 5x+x
120= 6x
120÷6=x
x=20.
Now , angle EFB = angle FGD= 5x = 5 × 20
= 100
Therefore,
angle EFB = angle FGD = 100°
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