In the figure, AB||CD, what is x+y?
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x+y=100
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100°
Solution:
x = 40° [Alternate interior angles]
y = 60° [Alternate interior angles]
x + y = 40° + 60° = 100°
or
Let the third angle of the triangle be z.
40° + 60° + z = 180° [Angle sum property]
100° + z = 180°
x + y + z = 180° [Angles on a line]
100° + z = x + y + z
x + y = 100°
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