Question

In the figure AB//CE and CD//EF. The value of X is

Answer 1

It is given that AB || CD and BC is a transversal From the figure we know that ∠BCD and ∠ABC are alternate interior angles So we get ∠ABC = ∠BCD

In order to find the value of x

we can write it as xo + ∠ECD = 70o ……. (1)

It is given that CD || EF and CE is a transversal From the figure we know that ∠ECD and ∠CEF are consecutive interior angles So we get ∠ECD + ∠CEF = 180°

By substituting the values ∠ECD + 130o = 180o

On further calculation we get

∠ECD = 180o – 130o

By subtraction ∠ECD = 50o

Now by substituting ∠ECD in equation (1)

we get xo + ∠ECD = 70o xo + 50o = 70o

On further calculation we get

xo = 70o – 50o

By subtraction xo = 20o

Therefore, the value of x is 20o.