Question

In the figure, AB//DC and AC and PQ intersect each other at point O such that OA ×CQ=OC×AP.

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Answer 1

Answer:

△APO and △CQO

∠AOP=∠COQ (vertically opposite angle)

∠APO=∠CQO (alternative angle)

∠PAO=∠QCO (alternative angle)

So, OA.CQ=OC.AP Hmm i didnt saw actually

Answer 2

Hope it helps u illena......be happy dear ☺️