In the figure AB = DC and angle BAD = angle CDA , prove that ΔBAD is congruent to ΔDAC , AC = Bd
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angle BAD is = angle DAC
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Given AB=AC,BD=DC
In △ADB,△ADC
AB=AC
BD=DC
AD=AD
By SSS congruency
△ADB≅△ADC
⟹∠ADB=∠ADC
and also ∠BAD=∠CAD
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