Question

in the figure AB equal 3cm AC equal 3 CM and angle A equal 50 then find angle B

Answer 1

In ∆ABC,
Seg AB=SegAC(given)
<B=<C(Isosceles triangle theorem)
In ∆ABC,
<A+<B+<C=180°(angle sum property)
50°+<B+<B=180°
50°+2<B=180°
2<B=180°-50°
2<B=130°
<B=130°÷2
<B=65°