In the figure. AB II CD, find the value of x.
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Answer:
x - 130 degree
Step-by-step explanation:
From E, draw EF || AB || CD. EF || CD and CE is the transversal.
∴∠DCE+∠CEF=180
o
[∵ Co-interior angles]
⇒x
o
+∠CEF=180
o
⇒∠CEF=(180−x
o
)
Again, EF || AB and AE is the transversal.
∠BAE+∠AEF=180
o
[∵ Co-interior angles]
⇒105
o
+∠AEC+∠CEF=180
o
⇒105
o
+25
o
+(180
)=180
⇒310−x
=180
Hence, x=130 degree
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