In the figure, AB Il CD. Find the value of x
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PEF=BEG=85°. (Vertically opposite angles)
BEG=DGQ= 85°. (Corresponding angles)
now, DGQ+QGH=180°. (LINEAR PAIR)
85° + QGH = 180°
.°. QGH= 95°
Similarly, QHC+QHG= 180° (linear pair)
115° + QHG = 180°
QHG= 65°
NOW,. QGH + QHG + x = 180° (ANGLE SUM PROPERTY)
95° + 65° + x = 180°
x= 180° - 160°
x= 20°
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