Question

In the figure, AB is diameter of the circle with centre O and BT is a tangent. If angle OQA=58 find angle BTQ

Answer 1

Angle ABQ=1/2 angle AOQ

=1/2*58

=29

Angle A =90(AT is a tangent)

angle BAT+angle ABT +angle ATQ=180(angle sum  

property of triangle.)  

90+29+angle ATQ= 180

angle ATQ=180-119

angle ATQ=61

HOPE THIS HELPS YOU