Question

in the figure AB is greater than AC show that AB is greater than AD​

Answer 1

Step-by-step explanation:

In ∆ABC AB > AC ⇒ ∠ACB > ∠ABC …(i) (∵ angle opposite to larger side is greater) Now in ∆ACD, CD is produced to B forming an ext ∠ADB. ∠ADB > ∠ACD (exterior angle of a A is greater than each interior opposite angle) ⇒ ∠ADB > ∠ACB …(ii) ∠ACD = ∠ACB From (i) and (ii) ∠ADB > ∠ABC ⇒ ∠ADB > ∠ABD [∵ ∠ABC = ∠ABD] ⇒ AB > AD [∵ side opposite to greater angle is larger] Hence Proved

Answer 2

Answer:

hence AB>AD (since greater angle has greater side to it)

Step-by-step explanation:

hope it is help full please mark me as brainlest to gain my next rank