Question

in the figure ab is parallel to CD find the value of x​

Answer 1

Step-by-step explanation:

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FG

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°∠CEG=80°

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°∠CEG=80°Now, ∠BEG=∠BEC+∠CEG

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°∠CEG=80°Now, ∠BEG=∠BEC+∠CEG120°=x+80°

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°∠CEG=80°Now, ∠BEG=∠BEC+∠CEG120°=x+80°x=40°

Let AB is parallel to FG, then ∠ABE=∠BEG=120°(Alternate angles)Also, it is given that CD is parallel to AB and we have assumed that AB is parallel to FG, then CD is parallel to FGTherefore, considering CD║FG and CE is the transversal, then∠DCE+∠CEG=180°(Co-interior angles)100°+∠CEG=180°∠CEG=80°Now, ∠BEG=∠BEC+∠CEG120°=x+80°x=40°Thus, the value of the ∠BEC=x=40°