In the figure,AB is parallel to CD,find x
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Answered by
1
Answer:
angle BAD=angle CDE=53 DEGREE
THE SUM OF A TRIANGLE IS 180 DEGREE
HENCE U CAN SEMPLIFY THAT
<CDE + <DCE + <CED=180°
38° + 53° + x = 180°
NOW U CAN SIMPLIFY IT EASIELY
Answered by
2
Explanation:
It is given that
∠BAD = 53°, ∠ECD = 38°, AB ║CD.
Since AD acts as a transversal for lines AB and CD, and ∠BAD and ∠ADC are alternate interior angles,
∠ADC = ∠EDC = 53° [∵ E is a point on line AD]
∴ In triangle CDE,
∠ECD + ∠EDC + ∠CED = 180°
==> 38° + 53° + x = 180°
==> x + 91° = 180°
==> x = 180° - 91°
∴ x = 89°
Answer: x = 89°
I hope this helps. :D
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