Math, asked by skywalkermd001, 5 hours ago

In the figure,AB is parallel to CD,find x ​

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Answered by sweetyj3030ss
1

Answer:

angle BAD=angle CDE=53 DEGREE

THE SUM OF A TRIANGLE IS 180 DEGREE

HENCE U CAN SEMPLIFY THAT

<CDE + <DCE + <CED=180°

38° + 53° + x = 180°

NOW U CAN SIMPLIFY IT EASIELY

Answered by negivardhan993
2

Explanation:

It is given that

∠BAD = 53°, ∠ECD = 38°, AB ║CD.

Since AD acts as a transversal for lines AB and CD, and ∠BAD and ∠ADC are alternate interior angles,

∠ADC = ∠EDC = 53° [∵ E is a point on line AD]

∴ In triangle CDE,

∠ECD + ∠EDC + ∠CED = 180°

==> 38° + 53° + x = 180°

==> x + 91° = 180°

==> x = 180° - 91°

∴ x = 89°

Answer: x = 89°

I hope this helps. :D

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