in the figure ab is parallel to CD find x
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angle a = angle d= 53degree
180-91=89.
x=89.
180-91=89.
x=89.
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Since AB//CD and AD is a transversal
so, angBAD=angEDC=53
In trangleEDC
angEDC+angDCE+angCED=180
53 + 38 + x = 180
81 + x = 180
x= 180 - 81
x=99 Answer
so, angBAD=angEDC=53
In trangleEDC
angEDC+angDCE+angCED=180
53 + 38 + x = 180
81 + x = 180
x= 180 - 81
x=99 Answer
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