In the figure, AB is parallel to CD, find x
AB = 48
CD=24
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Let us draw a line EF parallel to the lines AB and CD.
Then ∠BPF=∠ABP=48
o
[ alternate angle].......(1).
Also, ∠CPF=∠PCD=24
o
[ alternate angle]......(2).
Now
∠BPC=∠BPF+∠CPF=48 o +24 o =72 o
.Then x=360 o−72 o
=288 o
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