Question

in the figure AB is parallel to CD if <ABO = 130and<COD = 110 then find the value of <BOC​

Answer 1

Answer:

<BOC= 60°

Step-by-step explanation:

Given AB // CD

AF // CD ( AB is produced to F, CF is transversal)

<DCF = <BFC=110°

.

Now, <BFC +<BFO = 180° ( Sum of angles of linear pair is 180°)

<BFO = 180°- 110°

= 70°......

..Now in triangle BOF, we have

<ABO= <BFO +< BOF

130° = 70° +< BOF

< BOF = 130° - 70°

<BOF = 60°