In the figure AB is parallel to DC
a)Find all inner angles of the quadrilateral ABCD
b)Find all outer angles of the quadrilateral ABCD
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Step-by-step explanation:
(a) Here, AB||DC and AD And BC are the transversal
Now, Angle A+D = 180° ( co-interior angles are supplementary)
=> 95° + D = 180°
=> D = 180°–95°
=> D = 85°
Again Angle B+C = 180° ( co-interior angles are supplementary)
=> B+65°= 180°
=> B = 180°–65°
=> B = 115°
Thus, All interior angles are Angle A=95° , B = 115°, C= 65° , D= 85°
(b)
Measure of exterior angle of
A= 180°–95° (Linear pair)
=85°
B = 180°–115° =. 65°
C= 180°–65°=. 115°
D=180°–85° =. 95°
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