In the figure, AB is parallel to DC, if x = 4y+3, y = 3z+8, then find angle BCD, angle ABC, angle BAD.
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x = 4 y + 3
y = 3 z + 8
=> x = 12 z + 35
x + y = 180°
=> 15 z + 43 = 180°
=> z = 137/15 deg =
x = 12 * 137/15 + 35 = 133.6°
y = 35.4°
∠A = 133.6° ∠B = 90° - z = 80.87°
∠C = 90 + z = 99.13°
∠D = 133.6°
y = 3 z + 8
=> x = 12 z + 35
x + y = 180°
=> 15 z + 43 = 180°
=> z = 137/15 deg =
x = 12 * 137/15 + 35 = 133.6°
y = 35.4°
∠A = 133.6° ∠B = 90° - z = 80.87°
∠C = 90 + z = 99.13°
∠D = 133.6°
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