Question

In the figure AB is the diameter and C is the centre of the circle .Also CQ=QR and ANGLE CQR=140 degree.Find ANGLE DCA.Please solve in paper​

Answer 1

Answer:

Angle DCA = 60 degree

Step-by-step explanation:

Angle QCR = Angle QRC

= (180 - 140) / 2 = 20 degree

Angle CDQ = Angle CQD

Angle CQD = 180 - 140 = 40 degree

Therefore,

Angle QCD = 180 - (40 + 40) = 100 degree

Angle DCA = 180 - ( 100 + 20) = 60 degree