in the figure AB is the diameter. Angle BAC =55 degree Find angle ABC
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5
angle BAC= 55*
diameter of a circle subtend 90* angle on the circumference of the circle
therefore angle ACB =90
now
A+B+C= 180*. (angle sum prprty)
55*+90*+B=180*
145*+B=180*
B =180-145
B =35*
angle ABC =35*
diameter of a circle subtend 90* angle on the circumference of the circle
therefore angle ACB =90
now
A+B+C= 180*. (angle sum prprty)
55*+90*+B=180*
145*+B=180*
B =180-145
B =35*
angle ABC =35*
vaishakhgatty63:
thanks
Answered by
7
angle BAC = 55°
angle BCA = 90°(angle in a semicircle if equal to 90°)
angle ABC = 180°-(55+90)°
=180°-145°
=35°
PLEASE MARK IT AS BRAINILIEST ANSWER
angle BCA = 90°(angle in a semicircle if equal to 90°)
angle ABC = 180°-(55+90)°
=180°-145°
=35°
PLEASE MARK IT AS BRAINILIEST ANSWER
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