Question

in the figure AB is the diameter of the circle ACand PD are perpendicular to CD
a)what is the measure of angle APB?​

Answer 1

Answer:

60 degree

Step-by-step explanation:

In△OCD

OC=OB=CD

∴∠COD=60(Anglesofequilateraltriangle)

AS∠CAD=

2

1

∠COD=

2

1

×60=30

Now∠ADP=∠ADB=90(Angleinsemicircle)

In△ADP

∠ADP+∠DPA+∠DAP=180

⇒90+∠DPA+30=180

⇒∠DPA=180−120=60=∠APB