Question

In the figure AB is the diameter of the circle.
Radius of the circle is
5cm and <A=40° (a)what is the measure of <C?
b) what is the length of BC?
(hint: sin 40°= 0.64)​

Answer 1

Answer:

sorry

Step-by-step explanation:

weak in maths please pride on me

Answer 2

Answer:

CONSTRUCTION DRAW A STRAIGHT LINE C0 WHERE 0 iS centre OF CIRCE

∡0CB=<CB0 (base angle of isoceles triangle are equal)

∡0AC=<AC0 (base angle of isoceles triangle are equal)

∡AC0=40

∡ACB=∡AC0+∡0BC

         =40+∡0CB

∡ACB+∡CB0+∡BAC=180

40+∡OCB+∡OCB+40=180

∡OCB=50

∴∡ACB=50+40=90

FOR LENGTH OF BC

BC=√(R²+R²)

     √(25+25)

     √50 Cm