Question

In the figure AB is the diameter of the semicircle and PC is perpendicular to AB
PC=6cm, PB=3cm.
Find the radius of the circle​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

ANSWER

Let O be the centre of the circle. Then, OA=OB=OD=r

Now, OC=r−2

and CD=6

Thus, in △ODC

OC

2

+CD

2

=OD

2

(r−2)

2

+6

2

=r

2

r

2

+4−4r+36=r

2

4r=40

r=10 cm

Area of semicircle =

2

πr

2

=

2

π(10)

2

=50π