Question

in the figure AB is the diameter with ‘o’ as centre ,AP is a tangent .if angle OCB=25 DEGREE ,find angle APB

Answer 1

Where is the figure???

Answer 2

Answer:

Thus, our angle APB is equal to 65º.

Step-by-step explanation:

Our question is: in the figure AB is the diameter with ‘o’ as centre ,AP is a tangent .if angle OCB=25 DEGREE ,find angle APB.

In order to answer this question we have to consider that the sum of all angles of a triangle is equal to 180º, hence we have that OCB is equal to 25º.

Since AP is a tangent, we conclude that its adjacent angle is equal to 90º.

Hence, we can conclude that we have:

• 180º - (25º + 90º) = 180º - 115º = 65º

Thus, our angle APB is equal to 65º.