in the figure AB ll CD if ANGLE EPA=110° find angle BPQ AND ANGLE PQD
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EPA=110
As EF is a line EPA+BPQ=180 BECAUSE THEY ARE LINEAR PAIR
110+BPQ=180
BPQ=180-110
BPQ=70
APQ=EPB BECAUSE THEY ARE VERTICALLY OPPOSITE ANGLES
APQ=PQD BECAUSE THEY ARE ALTERNATE INTERIOR ANGLES
THEREFORE EPB=PQD
PQD=110
Good luck bye
As EF is a line EPA+BPQ=180 BECAUSE THEY ARE LINEAR PAIR
110+BPQ=180
BPQ=180-110
BPQ=70
APQ=EPB BECAUSE THEY ARE VERTICALLY OPPOSITE ANGLES
APQ=PQD BECAUSE THEY ARE ALTERNATE INTERIOR ANGLES
THEREFORE EPB=PQD
PQD=110
Good luck bye
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