In the figure, AB ll CD. Then x is 65° ?? is it true ??
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∴∠GEF=30o
and ∠GCD=∠GEF (from the figure, CD∣∣EF)
⇒∠GCD=30o
Now, ∠BCD=∠BCG+∠GCD
⇒∠BCD=25o+30o=55o
∠ABC=∠BCD(∵AB∣∣CD)
∠ABC=x=55o
Therefore the value of x is 55.
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yes it is true that x =65 degree
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True..X=65°
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