in the figure AB llCD and angle 1 and angle 2 are in the ratio 3 : 2 determine all angle from 1 to 8
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Note = I am considering TQ in place of AB
∠1 : ∠2 = 3 : 2
Assume
∠1 = 3p
∠2 = 2p
Line “Y” stands on the line T
∠1 + ∠2 = 180°
3p + 2p = 180°
5p = 180
p = 180÷5
p = 36
So,
∠1 = 3p = 3 × 36 = 108°
∠2 = 2p = 2 × 36 = 72°
Also,
∠1 = ∠5 = 108°[Pair of corresponding angles]
∠2 = ∠4 = 72° [V•O•A]
∠4 = ∠8 = 72° [Pair of corresponding angles]
∠2 = ∠6 = 72° [Pair of corresponding angles]
∠1 = ∠3 = 108° [V•O•A]
∠3 = ∠7 = 108° [Pair of corresponding angles]
Therefore
∠1 = ∠3 = ∠7 = ∠5 = 108°
∠2 = ∠4 = ∠8 = ∠6 = 72°
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