Question

in the figure ab parallel to CD and so is a transversal then find angle pqb

Answer 1

Heya mate here is your answer

2x+1+3x+4= 180° (angle on the same side of transversal)

=>5x+5=180°

=>5x= 175°

=>X= 175/5= 35°
=> 3x+ 4 = 3*35+4= 109°

So, anglePQB=109 °(vertically opposite angles)

Hope this helps you

Answer 2

Here Is The Answer:
∠AQR + ∠AQP = 180° [ linear pair ]
∠AQP = 2 x + 1 [ corresponding of  ∠CQR ]
3 x + 4 + 2 x + 1 = 180
3 x + 2 x + 4 + 1 = 180
5 x + 5 = 180
5 x = 180 - 5
5 x = 175
x = 175 / 5
   = 35°
 ∴ ∠ PQB = 3 x + 4 [ vertical opposite to ∠AQR ]
                = 3 [ 35 ] + 4
                = 105 + 4
                = 109°